x^2/5-5+x=-5

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Solution for x^2/5-5+x=-5 equation: 


x in (-oo:+oo)

(x^2)/5+x-5 = -5 // + 5

(x^2)/5+x-5+5 = 0

1/5*x^2+x = 0

DELTA = 1^2-(0*1/5*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-1)/(1/5*2) or x = (-1^(1/2)-1)/(1/5*2)

x = 0 or x = -5

x in { -5, 0 }

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